Be sure to answer all parts. compound a decomposes according to the equation a(g) ⇌ 2 b(g) + c (g) a sealed 1.00−l container initially contains 1.81 × 10−3 mol of a(g), 1.34 × 10−3 mol of b(g), and 6.37 × 10−4 mol of c(g) at 100°c. at equilibrium, [a] is 2.13 × 10−3 m. find [b] and [c]. solve for the equilibrium concentrations of b and c. [b]eq × 10 m [c]eq × 10 m

The equilibrium concentration of B is 1.98  × 10−3 M while the equilibrium concentration of C is 9.57  × 10−4 M.

We have to set up the ICE table as shown below;

Initial concentration of A =       1.81 × 10−3 mol/1.00 L = 1.81 × 10−3 M

Initial concentration of B =   1.34 × 10−3 mol/1. 00 L = 1.34 × 10−3 M

Initial concentration of C =  6.37 × 10−4 mol / 1.00 L = 6.37 × 10−4 M

     A(g) ⇌                      2 B(g)      +            C (g)

I    1.81 × 10−3           1.34 × 10−3                 6.37 × 10−4

C  - x                            +2x                             +x

E 1.81 × 10−3 - x       1.34 × 10−3 + 2x      6.37 × 10−4 + x

We know from the question that the equilibrium concentration of A is  2.13 × 10−3 M so;

2.13 × 10−3  =  1.81 × 10−3 - x

x = 2.13 × 10−3 - 1.81 × 10−3

x = 3.2  × 10−4 M

Hence;

Equilibrium concentration of B

1.34 × 10−3 + 2( 3.2  × 10−4)

= 1.98  × 10−3 M

Equilibrium concentration of C

6.37 × 10−4 + 3.2  × 10−4

= 9.57  × 10−4 M

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Equilibrium concentration of  

Equilibrium concentration of  

Explanation:

Initial moles of   =

Volume of container = 1.00 L

Initial concentration of  

Initial concentration of B=  

Initial concentration of

Equilibrium concentration of

The given balanced equilibrium reaction is,

Initial :            

At eqm:          

we are given :

Equilibrium concentration of  

Equilibrium concentration of  

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2h2o2--> 2h2o + o2

this reaction is of the spontaneous decomposition of hydrogen peroxide down into water and oxygen.

add 2 molecules of hydrogen peroxide and 2 molecules of water. since oxygen is naturally diatomic, the total number of atoms of each element is now the same on both sides of the equation so it is balanced.

this may not be entirely correct but let me know.