Determine the identity of each element based upon the following data.

period 3 element with the following ionization energies (kj/mole):
ie(1)= 1000 ie(2)= 2251 ie(3)= 3361 ie(4)= 4564 ie(5)= 7013 ie(6)= 8496 ie(7)= 27110

Ionization energy is defined as the energy required to remove the electron requiring the least amount of energy in the atom.

When valence electrons are being removed, the ionization energy will be quite low. However, once there is a spike in the number (In this case, IE6 starts at 8496 and jumps to 27110 in IE7), that indicates that a core electron is being removed.

Since there are 6 ionization energies that are relatively low before the spike in energy in IE(7), it can be inferred that this period 3 element has 6 valence electrons.

Because of this, we simply have to go from left to right in period 3 six times. (Make sure to skip over the transition metals if you're counting past period 3, since their valence electrons vary)

Sulfur is the mystery element

Good luck! If you have any questions, just ask! :))

in 1783 cavendish was working with his hydrogen gas and found that when he burned it and condensed the vapor it was water. this was very significant since it disproved the greek theory of elements completely since water was not a simple substance but the product of two gases. it was lavoisier who hearing of the experiment gave cavendish's gas the name hydrogen ("water-producer") and added that hydrogen burned by combining with oxygen and that water was a hydrogen-oxygen combination.

explanation:

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