What is the molarity of zncl2 that forms when 25.0 g of zinc completely reacts with cucl2 according to the following reaction? assume a final volume of 285 ml .
zn(s)+cucl2(aq)→zncl2(aq)+cu(s)

Molarity of is 1.364 M

Explanation:

Molarity of product Zinc Chloride which is formed when 25.0 g of Zinc completely reacts with copper(II) chloride:

Firstly no of moles of Zn can be obtained from :  

, molar mass of Zn = 65.38 g/mol  

hence moles of Zn = 25.0 g / 65.38 g/mol = 0.382 mol.

Now some conversion are needed to be done like:

1 m L = 0.001 L

Volume of solution = 285 mL

Hence 285 mL = 285 × 0.001 L = 0.28 L

Finally Molarity of can be calculated by:  

Molarity of  =

Molarity = = 1.364 M.

nacl or sodium chloride is an ionic compound. this is because an ionic compound pertains to a compound that consists of positively and negatively charged ions. in this case, na (sodium) has a tendency to lose one electron when it reacts with with other atoms, so the resulting sodium ion contains 11 protons and 10 electrons, thus making it positively charged (na+), when chlorine reacts, it usually gains one electron to form an ion called chloride, thus making it negatively charged ( since the ions are oppositely charged, they attract.