An alarm clock has a current of 4.5 amps and a resistance of 3.2 ohms. what is the voltage in the circuit? a. 1.4 volts b. 0.71 volts c. 14 volts d. 46 volts

14.4 V

Concept being tested: Current and electricity-Ohm's law

To answer this question we need to know the Ohm's law

In this case;

Current, I = 4.5 Amps

Resistance, R = 3.2 ohms

We are required to calculate the voltage.

But;

V=IR

   = (4.5 Amps × 3.2 ohms)

   = 14.4 V

Therefore, the voltage in the circuit is 14.4 V

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.