Vinegar is a dilute solution ethanoic acid in water (see the question above for the structure of ethanoic acid). in order to test the strength of a vinegar, a 10.00 gram sample was titrated with sodium hydroxide (0.1001 mole/kg of solution). the mass of the. burette before the titration is 131.44 g and upon reaching the endpoint the burette weighted 48.11 g. how many moles of acetic acid are in the sample?

Explanation:

Below is the equation of the chemical reaction:

CH3COOH (aq) + NaOH (aq) ----------> CH3COONa (aq) + H2O (l)

The mole ratio of acid and base in the balanced equation is:

Ma = 1, Mb = 1

Cb = 0.1001 mole/Kg

Ca = ???

Va = 10 grams

Vb = 131.44 - 48.11 = 83.33 grams

From the acid-base mole ration formula

The number of moles of acetic acid in the sample =

Therefore 0.008341333 moles of acetic acid are in the sample.

chemistry sucks a**

explanation:

answercontent filtering;