Chemistry, 15.11.2019 03:31 dozsyerra

Two factors that determine wether a molecule is polar are the types of atoms in the molecule and the of the molecule

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Answer from: nunezjazmine01

Shape

Explanation:

Two factors that determine wether a molecule is polar are the types of atoms in the molecule and the shape of molecule.

Shape and polarity determine which type of compounds is.

if the shape of molecule is symmetric it will non polar. And it will dissolve in non polar solvent. The polar molecules are trigonal in shape.

Sodium chloride is ionic compound. The electronegativity of chlorine is 3.16 and for sodium is 0.93. There is large difference is present. That's why electron from sodium is transfer to the chlorine. Sodium becomes positive and chlorine becomes negative ion and compound is polar.

The compound having ionic bonds generally have moderate to high boiling points and melting point because of greater electrostatic interaction. Their electrical conductivity are high and these minerals tend to dissolve in water.

Covalent bond:

It is formed by the sharing of electron pair between bonded atoms.

The atom with larger electronegativity attract the electron pair more towards it self and becomes partial negative while the other atom becomes partial positive and compound will polar.

For example:

In water the electronegativity of oxygen is 3.44 and hydrogen is 2.2. That's why electron pair attracted more towards oxygen, thus oxygen becomes partial negative and hydrogen becomes partial positive.

If the ectronegativity difference is 0.4 or less than this the compound will be non polar covalent compound and will behave different from polar compound.

Answer from: Quest

The density would be 1.622

Answer from: Quest

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. $hbr$ completely dissociates to $h^+$ and $br-$ ions. a is incorrect because $h_2s$ does not fully ionize to $h^+$ and $hs^-$ ions and some remain as the compound $h_2s$ . c and d are incorrect because, $li_2o$ and $libr$ do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise, if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both $li_2o$ and $libr$ have a complete octet so can not accept any electrons which disqualifies them as acids.

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Two factors that determine wether a molecule is polar are the types of atoms in the molecule and the...