Due to a highway accident, 150 l of concentrated hydrochloric acid (12.0 m) is released into a lake containing 5.0 ´ 105 m3 of water. if the ph of this lake was 7.0 prior to the accident, what is the ph of the lake following the accident?

The pH of the lake following the accident is 5.43.

Explanation:

Concentration of HCL =12.0 M

Volume of HCL = 150 L

Moles of hydrogen ions= n

The pH of the lake = 7

Concentration of hydrogen ions in lake =

Volume of water in lake  =

Moles of hydrogen ions in lake = n'

Concentration of hydrogen ions after release of HCL in lake: C

Total moles of HCl = n + n' = 1800 mol + 50 mol = 1850 mol

Volume of the lake =

The final pH of the lake:

=

The pH of the lake following the accident is 5.43.

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.

12 is it do you think so