When analyzed by tlc, a compound exhibited an rf value of 0.48 when diethyl ether was utilized as the developing solvent. in this analysis the solvent was allowed to travel a distance of 7.8 cm up the plate. if the solvent had been allowed to travel 11.3 cm up the plate how high up the plate would the compound have traveled?

5.4 cm

Explanation:

The Rf value can be calculated using the formula

Rf = A/B

Where A is the distance travelled by the compound, and B is the distance traveled by the solvent. If the compound and the developing solvent remain the same, the Rf value does not change, no matter the dimensions of the plate or how long the solvent was allowed to travel.

As such, we're left with Rf = 0.48 and B = 11.3 cm, so now we solve for A:

0.48 = A / 11.3

A = 5.4 cm

why do the isotopes of a particular element behave differently in nuclear reactions but the same in chemical reactions? chemical reactions involve changes to electrons in an atom; isotopes do not differ in electrons, and so they react the same way during chemical changes.

you need to take a look at the periodic system in order to sort these elements into pairs that would most likely exhibit similar chemical properties. first, you need to find elements that are found in the same group (groups are vertical in the periodic system), and then to see whether they have the same valence number. if they meet these criteria, they will have similar properties.

the first pair: ne (neon) and kr (krypton), are noble gases found in group 8

the second pair: li (lithium) and k (potassium), found in group 1

the third pair: s (sulfur) and te (tellurium), found in group 6