At an atmospheric pressure of 745 mm hg, what is the pressure of he gas inside a cylinder that is attached to an open-end manometer in which the level of mercury in the open side of the manometer is 25 mm hg higher than the side that is attached to the gas cylinder?

770 mmHg

Explanation:

For definition mmHg is a unit of medition of pressure equivalent to the pressure exerted by a column of mercury 1 millimeter high at 0°C and under the acceleration of gravity

So, If the level of mercury on the open side of the pressure gauge is 25 mm Hg higher than the side connected to the gas cylinder, 25mm Hg must be added to the atmospheric pressure

745mm Hg +25mmHg =770mmHg

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole