What is the maximum mass of zinc oxide that can be produced by the reaction of 42.96g of zinc sulfide and 44.1875g of oxygen?

Mass = 0.00541 g

Explanation:

We will convert the larger given values in to smaller by rounding these figures.

Given data:

Mass of zinc sulfide = 43 g

Mass of oxygen = 44.2 g

Mass of zinc oxide = ?

Solution:

Chemical equation:

2ZnS + 3O₂ → 2ZnO + 3SO₂

Number of moles of ZnS:

Number of moles = mass/ molar mass

Number of moles =  43 g/ 97.5 g/mol

Number of moles = 0.44 mol

Number of moles of Oxygen:

Number of moles = mass/ molar mass

Number of moles =  44.2 g/ 32 g/mol

Number of moles = 1.4 mol

Now we will compare the moles of oxygen and zinc sulfide with zinc oxide.

                             ZnS        :       ZnO

                                2          :          2

                              0.44       :         0.44

                              O₂          :          ZnO

                              3           :            2

                              1.4          :           2/3×1.4 =0.93

The number of moles of zinc oxide produced by ZnS are less so it will limiting reactant.

Mass of zinc oxide:

Mass = number of moles / molar mass

Mass = 0.44 mol / 81.38 g/mol

Mass = 0.00541 g

answer:

the answer is 6 valence electrons.

explanation:

valence is the # of electrons on the outer most shell of an atom.

oxygen has 6.

although, the valency of oxygen is 2, because it only needs to make 2 covalent bonds, or gain 2 electrons, to achieve the stable octet configuration of a noble gas.

that's it!

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~ trueboss72