Acell composed of a platinum indicator electrode and a silver-silver chloride reference electrode in a solution containing both fe2+ and fe3+ has a cell potential of 0.727 v. if the silver-silver chloride electrode is replaced with a saturated calomel electrode (sce), what is the new cell potential?

0.683 V

Explanation:

The saturated calomel electrode (SCE) is based on the following reaction:

0.5 Hg₂Cl₂(s) + e⁻ → Hg(l) + Cl⁻

If compared to the Standard Hydrogen Electrode, this electrode has a potential of +0.241 V, while the silver-silver chloride has a potential of +0.197 V.

So the new cell potential would be:

0.727 - (0.241 - 0.197) = 0.683 V

alkaline metals are lithium, sodium, rubidium, potassium, cesium and francium.

alkali metals have electronegativity from 0.7 to 1, lowest in periodic table of elements, which means that alkali metals (i group in periodic table) has positive oxidation number in compounds.

electronegativity is a chemical property that describes the tendency of an atom to attract a shared pair of electrons towards itself.

alkaline metals (far left in main group) have lowest ionizations energy and easy remove valence electrons,

for example, potassium is the alkali metal and has a single valence electron in the outer electron shell.

electron configuration of potassium is: ₁₉k 1s²2s²2p⁶3s²3p⁶4s¹.

they can not exist alone in nature, because they are very reactive.

it's all four options.