In a simplified version of the solar system model (developed by niels bohr, a danish chemist), an electron resides in an excited h atom orbit with an energy of -38.42 j (initial state). if the electron drops to a second orbit (final state) with the energy -63.33 j, a photon will be emitted. what will be the energy of the photon (j)?
can someone show how to solve this problem and explain.

-24.91 J

Explanation:

Energy of emitted Photon = Energy of final state -   Energy of initial state

                                           =  -63.33  -(-38.42)

                                           =  -24.91 J

The negative sign indicates that a photon was emitted.

c. because step up transformer steps up the input voltage i.e increases the input voltage  

the number of turns are greater on the secondary side of step up transformer  

transformer does not handle dc current