1.72 mol of licl in 37.5 l of solution

Molarity is 0.046 M

We are given;

1.72 mol of LiCl in 37.5 L of solution

We will take the question to be; calculate the molarity of LiCl

Therefore,

we can start by defining molarity as the concentration of a solution in moles per liter.

Molarity of a solution is calculated by dividing the number of moles of solute by the volume of solution.

Molarity = Moles of solute ÷ Volume of the solution

Thus, in this case;

Molarity of LiCl = Moles of LiCl ÷ Volume of the solution

                          = 1.72 moles ÷ 37.5 L

                          = 0.0459 M

                         = 0.046 M

Therefore, the molarity of LiCl solution is 0.046 M

false

because it does not have the potential to be entirely used up

i'm pretty sure its b i might be wrong though!