Calcium oxide reacts with water in a combination reaction to produce calcium hydroxide: cao (s) + h 2o (l) → ca(oh) 2 (s) in a particular experiment, a 2.00-g sample of cao is reacted with excess water and 2.14 g of ca(oh) 2 is recovered. what is the percent yield in this experiment?

The answer to your question is:  81%

Explanation:

Data

CaO = 2 g

Ca(OH)₂ = 2.14 g

Reaction balanced

                     CaO  +  H₂O   ⇒   Ca(OH)₂

Molecular mass

Calcium oxyde = 40 + 16 = 56 g

Calcium hydroxide = 40 + 2 + 32 = 74 g

Process

Rule of three

                               56 g of CaO --------------   74 g of Ca(OH)₂

                                 2 g  of CaO -------------   x

                                 x = (2 x 74) / 56

                                x = 2.64 g of Ca(OH)₂

Percent yield

                         % Yield =

                         % yield = 81