Asample consisting of various gases contains 3.2×10−6 mole fraction of radon. this gas at a total pressure of 34 atm is shaken with water at 30 ∘c. calculate the molar concentration of radon in the water. express your answer using two significant figures.

The molar concentration of radon is 4.38 x 10⁻⁶ mol.L⁻¹

Explanation:

Molar fraction = number of moles of a certain component / total number of moles

Partial pressure = Total pressure x molar fraction

Partial pressure = 34 atm x 3.2 x 10⁻⁶

Partial pressure = 1.09 x 10⁻⁴ atm

Considering radon as an ideal gas, PV = nRT

molar concentration = n/V

n/V = P/RT

n/V = 1.09 x 10⁻⁴ atm / 0.082 L.atm.mol⁻¹K⁻¹ x 303.15K

n/V = 4.38 x 10⁻⁶ mol.L⁻¹

the density(ratio between mass and volume as m/v) decreases from top to bottom in periodic table group as the size increases and nuclear charge decreases. but in periods density increases from left to right as atom size decreases and nuclear charge increases.

gas

explanation:

smoke is the matter of a gas