Compound o (c6h8) reacts with two molar equivalents of hydrogen in the presence of a catalyst to produce p (c6h12). the proton-decoupled 13c spectrum of o consists of two singlets, one at δ 26.0 and one at δ 124.5. in the dept 13c spectrum of o the signal at δ 26.0 appears as a ch2 group and the one at δ 124.5 appears as a ch group. note: all structures should be drawn with no bonds between carbon and hydrogen. draw the correct structure for o and p

Cyclohexadiene is converted to cyclohexane

Explanation:

Let's go in order of statements mentioned in question.

As we see from the formula it is a hydrocarbon. If it reacts with two equivalents of hydrogen, then it is either an alkyne or diene. Due to number of protons and only two signals in C13 NMR it must be a cyclic diene with only two types of Carbon atoms  wich is a cyclohexadiene (it supposes to have only two signals in NMR). The generated spectra on the second picture proves that. And after hydration it becomes ordinary cyclohexane.

in chemistry, a solution’s concentration is how much of a dissolvable substance, known as a solute, is mixed with another substance, called the solvent. the standard formula is c = m/v, where c is the concentration, m is the mass of the solute dissolved, and v is the total volume

what is the question here. i think you messed up.