what is the ph of a solution containing a 1.0 x 10−4 m solution of hcl?

1

4

1 x 104

1 x 10−4

4

Explanation:

HCl ⟶ H⁺ + Cl⁻

HCl dissociates completely in solution, so

1.0 × 10⁻⁴ mol·L⁻¹ HCl ⟶ 1.0 × 10⁻⁴ mol·L⁻¹ H⁺

pH = -log(H⁺) = -log(1.0 × 10⁻⁴) = -log(1.0) - log(10⁻⁴)= -0 - log(-4) = -(-4) = 4