2kclo_2 produces 2 kcl+ 3o_2 when heated. if this reaction produces 82.8 g of kcl how many grams of o2 were produced?

37.046 grams of oxygen gas were produced.

Explanation:

Moles of potassium chlorite =

According to reaction 2 moles of potassium chlorite gives 3 moles of oxygen gas.

Then 0.7718 moles of potassium chlorite will give:

of oxygen gas.

Mass of 1.1577 moles of oxygen gas:

1.1577 mol × 32 g/mol = 37.046 g

37.046 grams of oxygen gas were produced.

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

b. examine and describe cells