How many moles of a gas sample are in a 10.0 l container at 373 k and 203 kpa ?

0.33 mole

0.66 mole

1.11 moles

3.05 moles

0.66 mole is correct

The number of moles = 0.66  mole

Explanation:

Given as :

The volume of container (V) = 10.0 liter

The temperature (T)= 373 kelvin

The pressure of gas (P) = 203 k pa = 2.0034 atm

Let the number of mole = n

Now from at ideal gas law

PV = nRT

Where R = 0.08206 L atm per mol per kelvin

SO, (2.0034 × 10 ) = n × 0.08206 × 373

Or, (20.034 ) = n × 30.608

∴ n =

Or n = 0.654

Hence the number of mole  =  0.66 mole  Answer