Aphoton with a frequency of 5.29x1014 hz has_x10-19 j of energy.

3.505 × 10^-19 Joules

We are given;

Frequency = 5.29 x 10^14 Hz

We are required to calculate the energy of the photon.

Energy of a photon is given by the equation;

E = hf

where, h is the plank's constant, 6.626 × 10^-34 J-s

f is the frequency of the photon.

Therefore,

Energy = 6.626 × 10^-34 J-s × 5.29 x 10^14 Hz

            = 3.505 × 10^-19 Joules

Therefore, the energy of the photon is 3.505 × 10^-19 Joules

substituting a hydrogen atom with a halogen in a hydrocarbon:

- the single bond remains single. a is wrong.

- the bond with hydrogen is as strong as with a halogen. c is wrong

- a hydrocarbon is saturated if there is no double bond. we do not know that so d is wrong.

- carbon will always have four valence electrons. e is wrong.

by elimination, the correct answer is b. the boiling point of the new compound increases.