find the temperature (°c) of 1.25 moles of a gas if the gas has a volume 20.0 liters at a pressure of
1.75 atm.

T = 66.66 °C

Explanation:

Given data:

Moles of gas = 1.25 mol

Volume of gas = 20.0 L

Pressure of gas = 1.75 atm.

Temperature of gas = ?

Solution:

PV= nRT

T = PV/ nR

T = 1.75 atm × 20 L / 1.25 mol ×0.0821 atm. L. mol⁻¹ . K⁻¹

T = 35 atm. L / 0.103 atm. L. K⁻¹

T = 339.81 K

T = 339.81 K - 273.15 = 66.66 °C

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