The slightly soluble ionic compound pbf2 has a solubility in water of 0.74 g/l. what is the numerical value of ksp for pbf2?

Ksp =  1.08 × 10⁻⁷

Explanation:

Given data:

Solubility of PbF₂ = 0.74 g/L

Ksp for PbF₂ = ?

Solution:

PbF₂ → Pb⁺² + 2F⁻

Number of moles dissolved = 0.74 g/L /245.2 g/mol

Number of moles dissolved = 0.003 M

[Pb⁺²] = 0.003 M

[F⁻] = 0.003 M × 2 =  0.006 M

Ksp = [Pb⁺²] [F⁻]²

Ksp = (0.003 ) (0.006 )²

Ksp =  (0.003 ) (3.6 ×10⁻⁵)

Ksp =  1.08 × 10⁻⁷

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.