48. at 35°c, k = 1.6 x 10-5 for the reaction
2noci(g) = 2no(g) + cl2(g)
calculate the concentrations of all species at equilibrium
for each of the following original mixtures.
a. 2.0 moles of pure noci in a 2.0-l flask
b. 2.0 moles of no and 1.0 mole of cl2 in a 1.0-l
flask
c. 1.0 mole of noci and 1.0 mole of no in a 1.0-l
flask
d. 3.0 moles of no and 1.0 mole of cl2 in a 1.0-l
flask
e. 2.0 moles of noci, 2.0 moles of no, and 1.0 mole
of cl2 in a 1.0-l flask
f. 1.00 mol/l concentration of all three gases

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Answerthis solution will not form a precipitateexplanationsolubility equilbrium:         pbf₂(s)  ⇄ pb²⁺(aq) + 2 f⁻(aq)the solubility product expression is    (we exclude solids from the equilibrium expression).now suppose we have the trial ion product q, which we can define as    then, we can interpret  q as the product of the concentration of the ions that we have and ksp as the product of the ion concentrations that are needed to form a saturated solution.if q > ksp, then that implies that there will be a surplus of ions that exceed the amount that is required to form a saturated solution. a precipitate will then form (the precipitate continually  forms until the surplus ions are removed and q is decreased to ksp's value).if q = ksp, the saturated solution that forms is barely saturated and the precipitate will be minimal.if q < ksp, then the ion concentration will not be enough to form a saturated solution (so no precipitate).using our information, we calculate the trial ion product:     since q = 2.7  × 10⁻⁸ < ksp =  4  ×  10⁻⁸, a precipitate will not form.

The population of unionid mussels decreased after zebra mussels were introduced. zebra mussels competed with the unionid mussels for food. the zebra mussels were able to displace the unionid mussels, allowing the zebra mussel population to increase  over the years. the unionid mussel population decreased because  of lack of food.