Lemon juice has a ph of about 2.5. assuming that the acidity of lemon juice is due solely to citric acid, that citric acid is a monoprotic acid, and that the density of lemon juice is 1.0 g/ml, then the citric acid concentration calculates to 0.5% by mass. estimate the volume of 0.0100 m naoh required to neutralize a 3.71-g sample of lemon juice. the molar mass of citric acid is 190.12 g/mol.

The volume to neutralize the sample of lemon juice is 9,76mL

Explanation:

3,71 g sample of lemon juice are:

3,71 g × = 0,01855 g of citric acid. In moles:

0,01855 g × = 9,76x10⁻⁵ moles of citric acid.

Assuming this acid is a monoprotic acid, the moles of NaOH required to neutralized the citric acid are 9,76x10⁻⁵ moles

As the molar concentration of NaOH is 0,0100 mol/L. The volume to neutralize the sample of lemon juice is:

9,76x10⁻⁵ moles × = 9,76x10⁻³L ≡ 9,76 mL

I hope it helps!

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