Asample of water is heated from 10.0°c to 15.0°c by the addition of 125 j of heat. what is the
mass of the water?

5.97 g of water

Q = m × c × ΔT

In this case;

Quantity of heat, Q = 125 Joules

Change in temperature = 15°C - 10°C

                                       = 5°C

We know that the specific heat capacity of water is 4.186 J/g°C

Therefore, to get the mass we first rearrange the formula;

Mass = Q ÷ cΔT

        = 125 J ÷ (5°C × 4.186 J/g°C)

        = 5.97 g

Therefore, the mass of water is 5.97 g

The mass of a sample of water that is heated from 10.0°C to 15.0°C is 0.00595 kilograms.

Given the following data:

We know that the specific heat capacity of water is 4200 J/kg°C.

To find the  mass of the water:

Mathematically, quantity of heat is given by the formula;

Where:

Making mass the subject of formula, we have:

Substituting into the formula, we have:

Mass = 0.00595 kilograms

Therefore, the  mass of the water is 0.00595 kilograms.

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answer: the rate of diffusion increases with increase in temperature.

increase in temperature, increases the molecular/particles speed (kinetic energy. diffusion means movement of particles through the material.

generally, the heavier the particle the more it interacts with the environment and more the temperature matters. so higher temperature results in higher diffusion.