Consider the following balanced chemical equation, kcl(aq) agno3(aq) → agcl(s) kno3(aq)when a sample of impure potassium chloride (0.900 g) was dissolved in water, and treated with excess silver nitrate (agno3), 1.26 g of silver chloride (agcl) was precipitated. calculate the percentage kcl in the original sample.

In the original sample there's 72.78% KCl

Explanation:

KCl(aq) + AgNO₃(aq) → AgCl(s) + KNO₃(aq)

1.26 g AgCl *

8.792 * 10⁻³ mol KCl * 74.55 g/mol = 0.655 g KCl

0.655 / 0.900 * 100% = 72.78%

the positions which points up in upward carbon and down in downward carbon are axial

and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be

it is stable as it is in group 0 which have full outer shells of electrons