The empirical formula that contains 120 g of carbon and 30.3 g of hydrogen

Empirical formula is CH₃.

Explanation:

Given data:

Mass of carbon = 120 g

Mass of hydrogen = 30.3 g

Empirical formula = ?

Solution:

Number of gram atoms of C = 120 g / 12 g/mol = 10

Number of gram atoms of H = 30.3 g / 1.008 g/mol = 30.06

Atomic ratio:

                   C             :            H            

                10/10          :       30.06/10

                   1              :            3.06    

C : H  = 1 : 3

Empirical formula is CH₃.

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

24

the answer is d.) potassium