You have an naoh solution that has a concentration of 0.660 m and a volume of 50.0 milliliters. you dilute this solution with water to a total volume of 450.0 milliliters. what is the final concentration of the solution?

0.073 M

We are given;

Initial concentration, M1 of NaOH solution as 0.660 M

Initial volume,V1 of solution as 50.0 mL

Final volume,V2 of solution after dilution as 450 mL

We are required to calculate the final concentration, M2.

We are going to use the concept on dilution.

Using dilution formula,

M1V1 = M2V2

M2 = M1V1 ÷ V2

     = (0.660 M × 50.0 mL) ÷ 450.0 mL

     = 0.0733 M

     = 0.073 M

Thus, the final concentration of the solution is 0.073 M

a saline water is fed to a reverse osmosis unit at flow rate o rotameter connected to reject (retentate) line reads 8 installed in reject and permeate line reads 15.2 milli siemens/cm and 300 micro siemens/com respectively.