Identify each statement as either describing the limit of detection (lod) or the limit of quantitation (loq). a) the signal is equal to the average signal of the blank plus three times the standard deviation of the signal from the blank. b) it is the minimum amount of analyte that produces a signal which can be measured with reasonable accuracy. c) the concentration is equal to three times the standard deviation of the signal from the blank divided by the slope of the calibration curve. d the concentration is equal to 10 times the standard deviation of the signal from the blank divided by the slope of the calibration curve. e) it is the minimum amount of analyte that produces a signal that is significantly different from the blank.

for step 7 table c on the lab "newtons law of action"   the average time it took the car to travel .25 meters   was 1.92 seconds.

the average time it took the car to travel 0.50 meters was 2.61 seconds

hope this : )

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2