Arrange the events for the hydrolysis of amide bonds by chymotrypsin in their correct order. attack by ser 195 to give a tetrahedral intermediate protonation by his 57 and release of the free c-terminus of the hydrolyzed bond protonation by his 57 and release of the free n-terminus of the hydrolyzed bond attack by water, leading to formation of a tetrahedral intermediate binding of substrate to properly position the scissile bond for cleavage

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.