Write a balanced chemical equation for the reaction of zncl2 with excess naoh to produce na2zn(oh)4 sodium zincate. what mass of sodium zincate can be produced from 2.00 g of zncl2 with excess naoh by this reaction?

 

∴  
                                    =  
                                    =  0.0147 mol



                       1      :       1
∴ = 0.0147 mol

Mass = Molar Mass * Mol
∴  = [(23 * 2)+(65)+(16 * 4) + (1*4)] g/mol * 0.0147 mol
                                                       = 179 g/mol * 0.0147 mol
                                                       = 2.63 g

What? i don’t understand