Explain how you would calculate the q for warming 100.0 grams of liquid water from 0°c to 100 °c.

The answer to your question is:

Explanation:

Data

mass = 100 g

T1 = 0°C

T2 = 100 °C

C = 1 cal/g°C

Process

1.- Do a list of all the data given

2.- Look in books or tables the specific heat of water.

3.- Check that the variables have the same units

4.- Write the formula

5.- Substitute the data

6.- Do the operations

           Q = mC(T2 -T1)

           Q = 100(1)(100 - 0)

           Q = 100(100)

           Q = 10000 cal

n2(g) + 3h2-> 2nh3(g)   this is the balanced equation

note the mole ratio between n2, h2 and nh3.   it is 1 : 3 : 2   this will be important.

moles n2 present = 28.0 g n2 x 1 mole n2/28 g = 1 mole n2 present

moles h2 present = 25.0 g h2 x 1 mole h2/2 g = 12.5 moles h2 present

based on mole ratio, n2 is limiting in this situation because there is more than enough h2 but not enough n2.

moles nh3 that can be produced = 1 mole n2 x 2 moles nh3/mole n2 = 2 moles nh3 can be produced

grams of nh3 that can be produced = 2 moles nh3 x 17 g/mole = 34 grams of nh3 can be produced

note:   the key to this problem is recognizing that n2 is limiting, and therefore limits how much nh3 can be produced.