Indicate the concentration of each ion or molecule present in the following solutions: (a) 0.25 m nano3, ( b ) 1.3 * 10-2 m mgso4, ( c ) 0.0150 m c6h12o6, (d) a mixture of 45.0 ml of 0.272 m nacl and 65.0 ml of 0.0247 m 1nh422co3. assume that the volumes are additive.

For a: The concentration of sodium and nitrate ions are 0.25 M and 0.25 M respectively.

For b: The concentration of magnesium and sulfate ions are and respectively.

For c: The concentration of glucose solution is 0.0150 M

For d: The concentration of sodium, chloride, ammonium and carbonate ions in the mixture are 0.111 M, 0.111 M, 0.0146 M and 0.0146 M respectively.

Explanation:

The chemical equation for the ionization of sodium nitrate follows:

1 mole of sodium nitrate produces 1 mole of sodium ions and 1 mole of nitrate ions

Concentration of sodium ions = 0.25 M

Concentration of nitrate ions = 0.25 M

Hence, the concentration of sodium and nitrate ions are 0.25 M and 0.25 M respectively.

The chemical equation for the ionization of magnesium sulfate follows:

1 mole of magnesium sulfate produces 1 mole of magnesium ions and 1 mole of sulfate ions

Concentration of magnesium ions =

Concentration of sulfate ions =

Hence, the concentration of magnesium and sulfate ions are and respectively.

The given compound is a covalent compound and will not dissociate into its respective ions. So, the only chemical species present in the solution is

Hence, the concentration of glucose solution is 0.0150 M

To calculate the number of moles for given molarity, we use the equation:

    .....(1)

For sodium chloirde:

Molarity of NaCl solution = 0.272 M

Volume of solution = 45.0 mL

Putting values in equation 1, we get:

For ammonium carbonate:

Molarity of ammonium carbonate solution = 0.0247 M

Volume of solution = 65.0 mL

Putting values in equation 1, we get:

Total volume of the solution = 45 + 65 = 110 mL

Molarity of NaCl in the mixture =

Molarity of ammonium carbonate in the mixture =

The chemical equation for the ionization of sodium chloride follows:

1 mole of sodium chloride produces 1 mole of sodium ions and 1 mole of chloride ions

Concentration of sodium ions = 0.111 M

Concentration of chloride ions = 0.111 M

The chemical equation for the ionization of ammonium carbonate follows:

1 mole of ammonium carbonate produces 1 mole of ammonium ions and 1 mole of carbonate ions

Concentration of ammonium ions = 0.0146 M

Concentration of carbonate ions = 0.0146 M

Hence, the concentration of sodium, chloride, ammonium and carbonate ions in the mixture are 0.111 M, 0.111 M, 0.0146 M and 0.0146 M respectively.

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