Ablock of copper of unknown mass has an initial temperature of 65.4 degress celcuis. the copper is immersed in a beaker containing 95.7 g water at 22.7 degress celcius. when the two substances reach thermal equilibrium, the final temperature is 24.2 degrees celcius. what is the mass of the copper block?

The answer to your question is: m = 37.88 g

Explanation:

Data

                  Copper                   Water

mass               ?                          95.7 g

Cp               0.092 cal/g°C        1 cal/g°C

T1                65.4°C                     22.7°C

T2                24.2°C                    24.2°C

Formula

                   Q copper = Q water

Q = mCp(T2 - T1)

                  - m(0.092)(24.2 - 65.4) = 95.7(1)(24.2 - 22.7)

                   m = 95.7(1)(24.2 - 22.7) /- (0.92)(24.2 - 65.4)

                   m = 143.55 / 3.79

                   m = 37.88 g

answer by yourhope:

how do models compare to real-world objects?

d. most models represent a real-world object in a simpler way.

: )

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml