Enzyme a and enzyme b both catalyze the same reaction. if enzyme a has a larger turnover number than enzyme b, then which enzyme, if either, has a higher catalytic efficiency?

enzyme b is more efficient because it's turnover number is smaller.
enzyme a is more efficient because it's turnover number is larger.
not enough information is provided to know for certain.

Enzyme A, if we assume the concentration of the enzymes (A and B) are the same

Explanation:

As Enzyme turnover number is defined as the number of chemical conversions of substrate per second that a single enzyme can perform in its catalytic site, for a given enzyme concentration, we can say that the Enzyme A has a higher catalytic efficiency. This is true only if [Enzyme A] = [Enzyme B]

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

the answer is c i took the test