Escusez moi pour le dérangement, on m’a donné trois exercices à faire en physique-chimie j’en ai fait deux mais je ne suis pas sûre d’avoir juste voici ce que j’ai mis :

exercice 1:

1) il manque un titre sur le graphique.
2)la passe du dioxyde de carbone est de 220g lorsque la masse de carbone brûlée et de 55g.
3)la masse de carbone brûlée est d’environ 8g lorsque la masse de dioxyde de carbone forme est de 40 g.
4) le fait que sur un graphique qu’il y est une droite passe par l’origine cela signifie que le graphique est promotionnel (graphique de proportionnalité)

exercice 2:

1) le combustible est le carbone brûlé de 44g
2) le comburant est le dioxyde de carbone formé de 12g.
3) le nom du produit est dioxyde de carbone et les réactifs sont le carbone et le dioxygene
4) on fait ce calcul car on sait que co2 est la formule littéraire du dioxyde de carbone (co2 = 44g+12g = 56g)

merci d’advance de votre réponse .

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