A125g metal block at a temperature of 93.2 degrees celsius was immersed in 100g of water at 18.3 degrees celsius. given the specific heat of the metal (0.900 j/g degrees celsius), fund the final temperature of the block and the water

Final temperature is 34.2 °C

Explanation:

Given data:

mass of metal = 125 g

temperature of metal = 93.2 °C

mass of water v= 100 g

temperature of water = 18.3 °C

specific heat of meta is = 0.900 j/g. °C

specific heat of water is = 4.186  j/g. °C

final temperature of water and metal = ?

Solution:

Q = m . c . ΔT

ΔT = T2-T1

now we will put the values in equation

Q1 = m . c . ΔT

Q1 = 125 g. 0.900 j/g. °C .93.2°C - T2

Q1 = 112.5 (93.2°C - T2)

Q1 =10,485 - 112.5T2

Q2 = m . c . ΔT

Q2 = 100 . 4.186. (T2- 18.3)

Q2 = 418.6 . (T2- 18.3)

Q2 = 418.6T2 - 7660.38

10,485 - 112.5T2 = 418.6T2 - 7660.38

10,485 +  7660.38 =  418.6T2+  112.5T2

18145.38 = 531.1 T2

T2 = 18145.38/531.1

T2 = 34.2 °C

the best answer is d because the strong cohesion is caused by the ability of water molecules to undergo hydrogen bonding.

a is incorrect because when water solidifies, it becomes   ice, which expands and occupies a bigger volume for the same mass of water in its liquid state.

b is incorrect because water has high surface tension. besides bonding to itself it hydrogen bonds to other molecules at the top decreasing possibility for breaking of attractive forces.

c is incorrect because the water molecule has oxygen which is highly electronegative and so pulls the electron pair towards itself creating a dipole moment, making the molecule polar.

e is incorrect because water has strong adhesion, ability to stick to other molecules such as glass because of this molecules having stronger hydrogen bonding than water.

the objects have the same charge.