What is the value of the equilibrium constant for the reaction between cr(s) and cu^2+ (aq) at 25 degree c? cr(s) + cu^2+ (q)rightarrow cr^3+ (aq) + cu(s) if your calculator has overflow issues with this problem, you can use this identity to solve for k: if log(k) = x + y then k = 10^x times 10^y 3 times 10^109 -6 times 10^5 2 times 10^18 1 times 10^2 3 times 10^40

3 × 10¹⁰⁹

Explanation:

2Cr (s) → 2Cr³⁺ + 6e⁻        

and,

Ec° for the above reaction = 0.74 V

also,

3Cu²⁺ (aq) + 6e⁻ →   3Cu(s)

and,

Ea° for the above reaction = 0.34 V

Now,

The cell potential, E° = 0.34 + 0.74 = 1.08

E° =

thus,

0.34 =

here, n is the number of electrons exchanged

n = 6

1.08 =

or

㏒ k = 109.44

taking anti-log both sides

we get

k =  3 × 10¹⁰⁹

Hence, the answer is option (A) 3 × 10¹⁰⁹

the earth would become to overheated and everything alive on it will eventually die from overheating. plants will eventually die as well, water will evaporate, and it will be nothing but a hot planet without anything living on it.

c. is the answer

by love gaming