Chemistry, 18.10.2019 16:20 christyr2002
Barium chlorate (ba(clo3)2) breaks down to form barium chloride and oxygen. what is the balanced equation for this reaction? when counting atoms in parentheses, multiply all subscripts by the number outside the parentheses to get the number of atoms. bacl3(s) + o2(g) → bacl(s) + cl2(g) + o2(g) 2baocl3(s) → 2bacl(s) + cl2(g) + o2(g) ba(clo3)2(s) → bacl2(s) + o2(g) ba(clo3)2(s) → bacl2(s) + 3o2(g) 2ba(clo3)2(s) → bacl(s) + 6o2(g) ba(clo)2(s) → bacl2(s) + o2(g)
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Chemistry, 22.06.2019 02:00, bernicewhite156
Will give brainliest it is a lab from k12 here is the linkfor each metal that participated in a chemical change, write the type of metal it is, based on your examination of the periodic table. type your answer here. (score for question 3: of 5 points) were there any metallic compounds that did not react with either the acid or the base? write the type of metal, based on your examination of the periodic table. type your answer here. (score for question 4: of 5 points) make a general statement about the reactivity of the metals in this experiment. type your answer here.
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Barium chlorate (ba(clo3)2) breaks down to form barium chloride and oxygen. what is the balanced equ...
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