At the normal melting point of nacl, 801 degrees c, its enthalpy of fusion is 28.8 kj / mol. the density of the solid is 2.165 g/cm^3 , and the density of the liquid is 1.733 g/ cm^3. what pressure increase is needed to raise the melting point by 1.00 degrees c?

The increase in pressure is 0.003 atm

Explanation:

To calculate the final pressure, we use the Clausius-Clayperon equation, which is:

where,

= initial pressure which is the pressure at normal boiling point = 1 atm

= final pressure = ?

= Enthalpy change of the reaction = 28.8 kJ/mol = 28800 J/mol     (Conversion factor: 1 kJ = 1000 J)

R = Gas constant = 8.314 J/mol K

= initial temperature =

= final temperature =

Putting values in above equation, we get:

Change in pressure =

Hence, the increase in pressure is 0.003 atm

the product of the pressure and volume is also constant