1. plate boundaries using google earth. download the google earth file dynamic earth, it will outline the different plate boundaries. open google earth and go to file -open and choose the dynamic earth file. if you expand the file you'll see that there are several layers that you can turn on and off. for this activity you may want to turn off the seafloor age, volcanoes and earthquake layers. use the latitude/longitude coordinates given in the table below to determine the type of plate boundary at each location. these coordinates also match up with the descriptions in the table. type (or copy/paste) the coordinates into the search box in google earth and match up the locations and the geologic features/events to one of the listed plate boundaries. you may have to zoom out in order to see the location from the right perspective. each letter may be used > once. a. ocean-ocean convergent boundary b. ocean-continent convergent boundary c. continent-continent convergent boundary d. divergent boundary e. transform boundary latitudelongitude typ of la type of plate boundary latitude/longitude plate boundary 35.909 s, 72.733°w 27.988°n 86.925°e 38.322 n 142.369 e 4.00°s 12.24°vw 46.191°n 122.194°w 11.329°n, 142.206 e the deepest point on 35.900 n 120.433w earth the deepest point on earth san andreas fault highest point on earth 2011 japan 9.0 earthquake epicenter mt. st. helens, a well- known active volcando mid-atlantic ridge 2101 chile 8.8 earthquake epicenter

1.consider the following balanced equation and answer parts a through. show calculations for each part.  

3 ag(s) + 4 hno3(aq) → 3 agno3(aq) + no(g) + 2 h2o(l)  

a. calculate the number of moles of agno3 produced by the reaction of 3 moles of ag with excess hno3. if the number to the left of the compound represents the number of moles of the compound which are present, then 3 moles of ag react with 4 moles hno3 to produce 3 moles agno3 (aq).

so the answer to a would be 3 moles.

b. calculate the number of moles of agno3 produced by the reaction of 108 grams of ag with excess hno3.  

i'm not sure how to plug in the grams of silver into an equation using moles to find how many moles are produced.

c. calculate the number of grams of agno3 produced by the reaction of 108 grams of ag with excess hno3  

d. calculate the number of moles of no produced as a byproduct of the reaction of 108 grams of ag with excess hno3.  

e. calculate the number of grams of no produced as a byproduct starting with 108 grams of ag and excess hno3.  

explanation:

answer is: empirical formula is tl₂o. if we use 100 grams of compound, tha:

m(tl) = 96.2%  · 100 g ÷ 100%.

m(tl) = 96.2 g.

n(tl) = m(tl)  ÷ m(tl). n(tl) = 96.2 g  ÷ 204.4 g/mol.

n(tl) = 0.47 mol. m(o) = 3.77 g. n(o) = m(o)  ÷ m(o). n(o) = 3.77 g  ÷ 16 g/mol. n(ag) = 0.235 mol. n(tl) . n(o) = 0.47 mol : 0.235 mol /0.235. n(tl) . n(o) = 2 : 1.

m(tl₂o) = 204.4 g/mol  · 2 + 16 g/mol = 424.8 g/mol.

m(compound) = 456. 8 g/mol - 424.8 g/mol = 32 g/mol ( 2 oxygens); tl₂o₃.