Me ! super big hurry!

a 5 kg bowling ball is moving 0.2 m/s to the left. how much gravitational force is acting on the ball?

a) 49 n
b) 9.8 n
c) 1 n
d) 0.2 n

The answer to your question is: letter A

Explanation:

Data

mass = 5 kg

speed = 0.2 m/s

A) 49 N

B) 9.8 N

C) 1 N

D) 0.2 N

F = mass x gravity acceleration

F = 5 x 9.81

F = 49 N

Gravitational force is acting on the ball is 49N

Explanation:

given:

Mass of the bowling ball=5 kg

Speed at which the bowling ball is moving=0.2m/s

To find

gravitational force acting on the ball=?

solution:

The equation for the force of gravity is f=mg

where

f= force pulling the object

m=mass of the object

g= gravitational force and its value is

Substituting the known values

f=mg

f=(5)(9.8 )

f=49N

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

what is the question?