A3.0 m solution of hcl can be prepared from a 12.0 m solution by diluting 30 l of the 12.0 m solution ith suffient distilled water to a final volume of

Final volume is 120 L

According to the dilution equation;

M1V1 = M2V2

Where, M1 is the molarity  and V1 is the volume of the concentrated solution, while M2 and V2 are the molarity and volume of the diluted solution respectively.

In this case;

M1 = 12.0 M

V1 = 30 L

M2 = 3.0 M

V2 = ?

Therefore;

V2 = M1V1 ÷ M2

    = (12 × 30) ÷ 3

   = 120 L

Hence, the final volume will be 120 liters

hcl + naoh → h2o + nacl

explanation:

hcl + naoh → h2o + nacl   is the reaction that is correctly balanced.

however, pcl3 + h2 → ph3 +3hcl, 2ca+ 3cl2 → cacl3, and c5h12 + 5o2 → 5co2 + 6h2o are not correctly balanced.