Impure phosphoric acid for use in the manufacture of fertilizers is produced by the reaction of sulfuric acid on phosphate rock, of which a principal component is ca3(po4)2. the reaction is ca3(po4)2(s) + 3 h2so4(aq) → 3 caso4(s) + 2 h3po4(aq) how many moles of h3po4 can be produced from the reaction of 186.8 kg of h2so4? answer in units of mol.

1271 mol

Explanation:

The balanced reaction is

Ca₃(PO₄)₂(s) +3H₂SO₄(aq) →  3CaSO₄(s) + 2H₃PO₄(aq)

So, the stoichiometry of the reaction (the proportion of the substances) is 3 mol of H₂SO₄ for 2 mol of H₃PO₄. The molar masses are H= 1 g/mol, S = 32 g/mol, O = 16 g/mol, so:

H₂SO₄  = 2x1 + 1x32 + 4x16 = 98 g/mol

The number of moles is the mass divided by the molar mass, so for 186.8 kg (186800 g) of H₂SO₄

n = 186800/98 = 1906.12 mol

So, the stoichiometry calculus is:

3 mol of H₂SO₄ 2 mol of H₃PO₄

1906.12 mol of H₂SO₄ x

By a simple direct three rule:

3x = 3812.24

x = 1271 mol of H₃PO₄

2b2t

explanation:

2b2t

one negative thing it that it can kill water animals. another negative thing is it can cause the destruction of ecosystem. one way water pollution can be reduced is to conserve energy.