For the following reaction,
carbon monoxide+oxygen=carbon dioxide
0.414 moles of carbon monoxide are mixed with 0.418 moles of oxygen gas.
1.what is the formula for the limiting reagent?
2. what is the maximum amount of carbon dioxide that can be produced?

The answer to your question is:

1.- CO

2.- 0.414 moles of CO2

Explanation:

Data

                               2CO   + O2      ⇒    2CO2

CO = 0.414 moles

O2 = 0.418

Process

theoretical ratio   CO/O2 = 2/1 = 1

experimental ratio  CO/O2 = 0.414/0.418 = 0.99

Then the limiting reactant is CO

2.-

                    2 moles of CO  2 moles of CO2

                    0.414 moles of CO  x

                   x = (0.414 x 2) / 2

                   x = 0.414 moles of CO2

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