Aball at rest starts rolling down a hill with a constant acceleration of 3.2 meters/second2. what is the final velocity of the ball after 6.0 seconds? a. –9.6 meters/second b. 9.6 meters/second c. –19 meters/second d. 19 meters/second

D. 19 m/sec to the nearest whole number.

Explanation:

v = u + at   where u = initial  velocity, v = final velocity a = acceleration and t = time.

v = 0 + 3.2 * 6

= 19.2.

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

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