Elemental analysis of the unknown gas from part a revealed that it is 30.45% n and 69.55% o. what is the molecular formula for this gas?

The answer to your question is:   NO₂

Explanation:

Data

N = 30.45% = 30.45 g

O = 69.55% = 69.55 g

MW N = 14 g

MW O = 16 g

                         14 g of N  1 mol

                         30.45 g     x

                         x = (30.45 x 1) / 14

                         x = 2.18 mol of N

                         16 g of O   1 mol

                         69.55 g   x

                         x = (69.55 x 1) / 16

                        x = 4.35 mol of O

Divide by the lowest number of moles

For N = 2.18 / 2.18 = 1

For O = 4.35 / 2.18 = 1.99 ≈ 2.0

Formula =   NO₂

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