Chemistry, 11.10.2019 03:00 sairaanwar67

(a) 2 c6h6(l) + 15 o2(g) → 12 co2(g) + 6 h2o(l) (b) c2h3o2-(aq) + h3o+(aq) → hc2h3o2(aq) + h2o(l) (c) 4 h+(aq) + 4 co2+(aq) + o2(g) + 24 nh3(aq) → 4 co(nh3)63+(aq) + 2 h2o(l) (d) caco3(s) → cao(s) + co2(g) (e) 2 h2o2(l) → o2(g) + 2 h2o(l) the reaction in which a single species is both oxidized and reduced

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Answer from: mrym7d

The reaction (E) 2 H₂O₂ (l) → O₂ g) + 2 H₂O (l) has a single species that is both oxidized and reduced.

Explanation:

Given the reaction (E):

2 H₂O₂ (l) → O₂ g) + 2 H₂O (l)

In hydrogen peroxide, oxygen has an oxidation state of -1. We can see that the reaction is balanced.

The products of the reaction are:

O₂ (the oxidation state of the Oxygen is 0)

H₂O (the oxidation state of the Oxygen is -2)

Hence, 1 mol of Oxygen changes its oxidation state from -1 to 0 (oxidation) and 1 mol of Oxygen changes its oxidation state from -1 to -2 (reduction).

The reaction (E) has a single species that is both oxidized and reduced.

Answer from: Quest

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form( $n_2$ ) .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

Answer from: Quest

Adozen is 1221/12 = 1.751.75 x 12 = 21therefore, 1.75 is the answer.

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(a) 2 c6h6(l) + 15 o2(g) → 12 co2(g) + 6 h2o(l) (b) c2h3o2-(aq) + h3o+(aq) → hc2h3o2(aq) + h2o(l) (c...