Aparticular fluid has a shear stress of 0.005 n m-at a shear rate of 1 s- and a shear stress of 2 n m-2 at a shear rate of 50 - present an argument as to whether this fluid is newtonian or non-newtonian.

The given fluid is Non-Newtonian

Explanation:

Given:

τ₁ = 0.005 N/m²

 = 1 s⁻¹

τ₂ = 2 N/m²

 = 50 s⁻¹

Now,

From Newton's law of viscosity

τ =

Here, μ is the dynamic viscosity of the fluid

thus,

for the first case

0.005 = μ₁ × 1

or

μ₁ = 0.005 Pa.s

similarly

For the second case

2 = μ₂ × 50

or

μ₂ = 0.04 Pa.s

Since,

μ₁ ≠ μ₂

The given fluid is Non-Newtonian

as for the Newtonian Fluid the value of dynamic viscosity remains constant

n+h→nh3

we must remember that nitrogen and hydrogen are both diatomic molecules in their standard gas form. this adjusts the equation to

n2+h2→nh3

now we need to adjust coefficients in order to balance the atoms on each side of the equation. currently we have 2 atoms of nitrogen and 2 atoms of hydrogen on the reactant side and 1 atom of nitrogen and 3 atoms of hydrogen on the product side.

we can balance the hydrogens by placing a coefficient of 2 in front of ammonia and a coefficient of 3 in front of the hydrogen.

n2+3h2→2nh3

this gives us 6 hydrogen on each side and coincidentally the nitrogens now equal 2 on each side.