The titration of .1500 g of unknown acid required 43.65 ml of .103 m naoh to reach endpoint. what is the molecular weight of unknown solid

The molecular weight of unknown acid is 33.33 g

    HX(aq)+ NaOH(aq) → NaX(aq)+ H₂O(l)

We need to determine the molecular weight of the acid;

Number of moles is given by multiplying molarity and volume of the solution.

Number of moles = Molarity × Volume

                            = 0.103 M × 0.04365 L

                           = 0.0045 Moles NaOH

The mole ratio of the acid to NaOH is 1:1

Therefore; the moles of the acid will be 0.0045 moles

Moles of the acid that reacted are 0.0045 moles

Mass of the acid in 0.0045 moles is 0.1500 g

Therefore;

Molecular weight = mass ÷ moles

                            = 0.1500 g ÷ 0.0045 moles

                            = 33.33 g/mol

Therefore, the molecular weight of the acid in grams is 33.33 g

im pretty sure its b